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if [latex] n=\frac { \sqrt { 3 } }{ 2 } [/latex] then [latex] \frac { 1+n }{ 1+\sqrt { 1+n } } +\frac { 1-n }{ 1-\sqrt { 1-n } } [/latex]

A) 0

B) 1

C) 2

D) √3

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